Open Source Computer Vision Library https://opencv.org/
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/***********************************************************************
* Software License Agreement (BSD License)
*
* Copyright 2008-2009 Marius Muja (mariusm@cs.ubc.ca). All rights reserved.
* Copyright 2008-2009 David G. Lowe (lowe@cs.ubc.ca). All rights reserved.
*
* THE BSD LICENSE
*
* Redistribution and use in source and binary forms, with or without
* modification, are permitted provided that the following conditions
* are met:
*
* 1. Redistributions of source code must retain the above copyright
* notice, this list of conditions and the following disclaimer.
* 2. Redistributions in binary form must reproduce the above copyright
* notice, this list of conditions and the following disclaimer in the
* documentation and/or other materials provided with the distribution.
*
* THIS SOFTWARE IS PROVIDED BY THE AUTHOR ``AS IS'' AND ANY EXPRESS OR
* IMPLIED WARRANTIES, INCLUDING, BUT NOT LIMITED TO, THE IMPLIED WARRANTIES
* OF MERCHANTABILITY AND FITNESS FOR A PARTICULAR PURPOSE ARE DISCLAIMED.
* IN NO EVENT SHALL THE AUTHOR BE LIABLE FOR ANY DIRECT, INDIRECT,
* INCIDENTAL, SPECIAL, EXEMPLARY, OR CONSEQUENTIAL DAMAGES (INCLUDING, BUT
* NOT LIMITED TO, PROCUREMENT OF SUBSTITUTE GOODS OR SERVICES; LOSS OF USE,
* DATA, OR PROFITS; OR BUSINESS INTERRUPTION) HOWEVER CAUSED AND ON ANY
* THEORY OF LIABILITY, WHETHER IN CONTRACT, STRICT LIABILITY, OR TORT
* (INCLUDING NEGLIGENCE OR OTHERWISE) ARISING IN ANY WAY OUT OF THE USE OF
* THIS SOFTWARE, EVEN IF ADVISED OF THE POSSIBILITY OF SUCH DAMAGE.
*************************************************************************/
#ifndef ALLOCATOR_H
#define ALLOCATOR_H
#include <stdlib.h>
#include <stdio.h>
namespace cvflann
{
/**
* Allocates (using C's malloc) a generic type T.
*
* Params:
* count = number of instances to allocate.
* Returns: pointer (of type T*) to memory buffer
*/
template <typename T>
T* allocate(size_t count = 1)
{
T* mem = (T*) ::malloc(sizeof(T)*count);
return mem;
}
/**
* Pooled storage allocator
*
* The following routines allow for the efficient allocation of storage in
* small chunks from a specified pool. Rather than allowing each structure
* to be freed individually, an entire pool of storage is freed at once.
* This method has two advantages over just using malloc() and free(). First,
* it is far more efficient for allocating small objects, as there is
* no overhead for remembering all the information needed to free each
* object or consolidating fragmented memory. Second, the decision about
* how long to keep an object is made at the time of allocation, and there
* is no need to track down all the objects to free them.
*
*/
const size_t WORDSIZE=16;
const size_t BLOCKSIZE=8192;
class PooledAllocator
{
/* We maintain memory alignment to word boundaries by requiring that all
allocations be in multiples of the machine wordsize. */
/* Size of machine word in bytes. Must be power of 2. */
/* Minimum number of bytes requested at a time from the system. Must be multiple of WORDSIZE. */
int remaining; /* Number of bytes left in current block of storage. */
void* base; /* Pointer to base of current block of storage. */
void* loc; /* Current location in block to next allocate memory. */
int blocksize;
public:
int usedMemory;
int wastedMemory;
/**
Default constructor. Initializes a new pool.
*/
PooledAllocator(int blocksize = BLOCKSIZE)
{
this->blocksize = blocksize;
remaining = 0;
base = NULL;
usedMemory = 0;
wastedMemory = 0;
}
/**
* Destructor. Frees all the memory allocated in this pool.
*/
~PooledAllocator()
{
void *prev;
while (base != NULL) {
prev = *((void **) base); /* Get pointer to prev block. */
::free(base);
base = prev;
}
}
/**
* Returns a pointer to a piece of new memory of the given size in bytes
* allocated from the pool.
*/
void* malloc(int size)
{
int blocksize;
/* Round size up to a multiple of wordsize. The following expression
only works for WORDSIZE that is a power of 2, by masking last bits of
incremented size to zero.
*/
size = (size + (WORDSIZE - 1)) & ~(WORDSIZE - 1);
/* Check whether a new block must be allocated. Note that the first word
of a block is reserved for a pointer to the previous block.
*/
if (size > remaining) {
wastedMemory += remaining;
/* Allocate new storage. */
blocksize = (size + sizeof(void*) + (WORDSIZE-1) > BLOCKSIZE) ?
size + sizeof(void*) + (WORDSIZE-1) : BLOCKSIZE;
// use the standard C malloc to allocate memory
void* m = ::malloc(blocksize);
if (!m) {
fprintf(stderr,"Failed to allocate memory.");
exit(1);
}
/* Fill first word of new block with pointer to previous block. */
((void **) m)[0] = base;
base = m;
int shift = 0;
//int shift = (WORDSIZE - ( (((size_t)m) + sizeof(void*)) & (WORDSIZE-1))) & (WORDSIZE-1);
remaining = blocksize - sizeof(void*) - shift;
loc = ((char*)m + sizeof(void*) + shift);
}
void* rloc = loc;
loc = (char*)loc + size;
remaining -= size;
usedMemory += size;
return rloc;
}
/**
* Allocates (using this pool) a generic type T.
*
* Params:
* count = number of instances to allocate.
* Returns: pointer (of type T*) to memory buffer
*/
template <typename T>
T* allocate(size_t count = 1)
{
T* mem = (T*) this->malloc((int)(sizeof(T)*count));
return mem;
}
};
}
#endif //ALLOCATOR_H