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417 lines
13 KiB
417 lines
13 KiB
// Copyright 2011 Google Inc. All Rights Reserved. |
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// |
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// Use of this source code is governed by a BSD-style license |
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// that can be found in the COPYING file in the root of the source |
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// tree. An additional intellectual property rights grant can be found |
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// in the file PATENTS. All contributing project authors may |
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// be found in the AUTHORS file in the root of the source tree. |
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// ----------------------------------------------------------------------------- |
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// |
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// Author: Jyrki Alakuijala (jyrki@google.com) |
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// |
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// Entropy encoding (Huffman) for webp lossless. |
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#include <assert.h> |
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#include <stdlib.h> |
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#include <string.h> |
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#include "./huffman_encode_utils.h" |
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#include "./utils.h" |
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#include "../webp/format_constants.h" |
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// ----------------------------------------------------------------------------- |
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// Util function to optimize the symbol map for RLE coding |
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// Heuristics for selecting the stride ranges to collapse. |
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static int ValuesShouldBeCollapsedToStrideAverage(int a, int b) { |
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return abs(a - b) < 4; |
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} |
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// Change the population counts in a way that the consequent |
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// Huffman tree compression, especially its RLE-part, give smaller output. |
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static void OptimizeHuffmanForRle(int length, uint8_t* const good_for_rle, |
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uint32_t* const counts) { |
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// 1) Let's make the Huffman code more compatible with rle encoding. |
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int i; |
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for (; length >= 0; --length) { |
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if (length == 0) { |
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return; // All zeros. |
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} |
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if (counts[length - 1] != 0) { |
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// Now counts[0..length - 1] does not have trailing zeros. |
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break; |
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} |
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} |
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// 2) Let's mark all population counts that already can be encoded |
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// with an rle code. |
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{ |
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// Let's not spoil any of the existing good rle codes. |
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// Mark any seq of 0's that is longer as 5 as a good_for_rle. |
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// Mark any seq of non-0's that is longer as 7 as a good_for_rle. |
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uint32_t symbol = counts[0]; |
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int stride = 0; |
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for (i = 0; i < length + 1; ++i) { |
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if (i == length || counts[i] != symbol) { |
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if ((symbol == 0 && stride >= 5) || |
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(symbol != 0 && stride >= 7)) { |
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int k; |
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for (k = 0; k < stride; ++k) { |
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good_for_rle[i - k - 1] = 1; |
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} |
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} |
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stride = 1; |
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if (i != length) { |
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symbol = counts[i]; |
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} |
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} else { |
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++stride; |
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} |
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} |
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} |
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// 3) Let's replace those population counts that lead to more rle codes. |
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{ |
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uint32_t stride = 0; |
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uint32_t limit = counts[0]; |
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uint32_t sum = 0; |
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for (i = 0; i < length + 1; ++i) { |
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if (i == length || good_for_rle[i] || |
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(i != 0 && good_for_rle[i - 1]) || |
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!ValuesShouldBeCollapsedToStrideAverage(counts[i], limit)) { |
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if (stride >= 4 || (stride >= 3 && sum == 0)) { |
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uint32_t k; |
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// The stride must end, collapse what we have, if we have enough (4). |
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uint32_t count = (sum + stride / 2) / stride; |
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if (count < 1) { |
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count = 1; |
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} |
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if (sum == 0) { |
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// Don't make an all zeros stride to be upgraded to ones. |
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count = 0; |
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} |
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for (k = 0; k < stride; ++k) { |
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// We don't want to change value at counts[i], |
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// that is already belonging to the next stride. Thus - 1. |
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counts[i - k - 1] = count; |
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} |
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} |
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stride = 0; |
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sum = 0; |
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if (i < length - 3) { |
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// All interesting strides have a count of at least 4, |
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// at least when non-zeros. |
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limit = (counts[i] + counts[i + 1] + |
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counts[i + 2] + counts[i + 3] + 2) / 4; |
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} else if (i < length) { |
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limit = counts[i]; |
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} else { |
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limit = 0; |
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} |
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} |
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++stride; |
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if (i != length) { |
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sum += counts[i]; |
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if (stride >= 4) { |
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limit = (sum + stride / 2) / stride; |
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} |
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} |
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} |
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} |
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} |
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// A comparer function for two Huffman trees: sorts first by 'total count' |
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// (more comes first), and then by 'value' (more comes first). |
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static int CompareHuffmanTrees(const void* ptr1, const void* ptr2) { |
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const HuffmanTree* const t1 = (const HuffmanTree*)ptr1; |
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const HuffmanTree* const t2 = (const HuffmanTree*)ptr2; |
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if (t1->total_count_ > t2->total_count_) { |
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return -1; |
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} else if (t1->total_count_ < t2->total_count_) { |
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return 1; |
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} else { |
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assert(t1->value_ != t2->value_); |
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return (t1->value_ < t2->value_) ? -1 : 1; |
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} |
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} |
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static void SetBitDepths(const HuffmanTree* const tree, |
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const HuffmanTree* const pool, |
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uint8_t* const bit_depths, int level) { |
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if (tree->pool_index_left_ >= 0) { |
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SetBitDepths(&pool[tree->pool_index_left_], pool, bit_depths, level + 1); |
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SetBitDepths(&pool[tree->pool_index_right_], pool, bit_depths, level + 1); |
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} else { |
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bit_depths[tree->value_] = level; |
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} |
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} |
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// Create an optimal Huffman tree. |
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// |
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// (data,length): population counts. |
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// tree_limit: maximum bit depth (inclusive) of the codes. |
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// bit_depths[]: how many bits are used for the symbol. |
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// |
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// Returns 0 when an error has occurred. |
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// |
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// The catch here is that the tree cannot be arbitrarily deep |
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// |
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// count_limit is the value that is to be faked as the minimum value |
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// and this minimum value is raised until the tree matches the |
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// maximum length requirement. |
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// |
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// This algorithm is not of excellent performance for very long data blocks, |
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// especially when population counts are longer than 2**tree_limit, but |
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// we are not planning to use this with extremely long blocks. |
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// |
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// See http://en.wikipedia.org/wiki/Huffman_coding |
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static void GenerateOptimalTree(const uint32_t* const histogram, |
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int histogram_size, |
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HuffmanTree* tree, int tree_depth_limit, |
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uint8_t* const bit_depths) { |
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uint32_t count_min; |
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HuffmanTree* tree_pool; |
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int tree_size_orig = 0; |
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int i; |
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for (i = 0; i < histogram_size; ++i) { |
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if (histogram[i] != 0) { |
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++tree_size_orig; |
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} |
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} |
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if (tree_size_orig == 0) { // pretty optimal already! |
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return; |
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} |
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tree_pool = tree + tree_size_orig; |
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// For block sizes with less than 64k symbols we never need to do a |
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// second iteration of this loop. |
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// If we actually start running inside this loop a lot, we would perhaps |
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// be better off with the Katajainen algorithm. |
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assert(tree_size_orig <= (1 << (tree_depth_limit - 1))); |
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for (count_min = 1; ; count_min *= 2) { |
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int tree_size = tree_size_orig; |
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// We need to pack the Huffman tree in tree_depth_limit bits. |
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// So, we try by faking histogram entries to be at least 'count_min'. |
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int idx = 0; |
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int j; |
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for (j = 0; j < histogram_size; ++j) { |
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if (histogram[j] != 0) { |
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const uint32_t count = |
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(histogram[j] < count_min) ? count_min : histogram[j]; |
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tree[idx].total_count_ = count; |
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tree[idx].value_ = j; |
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tree[idx].pool_index_left_ = -1; |
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tree[idx].pool_index_right_ = -1; |
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++idx; |
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} |
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} |
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// Build the Huffman tree. |
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qsort(tree, tree_size, sizeof(*tree), CompareHuffmanTrees); |
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if (tree_size > 1) { // Normal case. |
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int tree_pool_size = 0; |
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while (tree_size > 1) { // Finish when we have only one root. |
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uint32_t count; |
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tree_pool[tree_pool_size++] = tree[tree_size - 1]; |
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tree_pool[tree_pool_size++] = tree[tree_size - 2]; |
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count = tree_pool[tree_pool_size - 1].total_count_ + |
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tree_pool[tree_pool_size - 2].total_count_; |
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tree_size -= 2; |
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{ |
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// Search for the insertion point. |
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int k; |
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for (k = 0; k < tree_size; ++k) { |
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if (tree[k].total_count_ <= count) { |
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break; |
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} |
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} |
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memmove(tree + (k + 1), tree + k, (tree_size - k) * sizeof(*tree)); |
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tree[k].total_count_ = count; |
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tree[k].value_ = -1; |
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tree[k].pool_index_left_ = tree_pool_size - 1; |
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tree[k].pool_index_right_ = tree_pool_size - 2; |
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tree_size = tree_size + 1; |
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} |
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} |
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SetBitDepths(&tree[0], tree_pool, bit_depths, 0); |
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} else if (tree_size == 1) { // Trivial case: only one element. |
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bit_depths[tree[0].value_] = 1; |
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} |
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{ |
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// Test if this Huffman tree satisfies our 'tree_depth_limit' criteria. |
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int max_depth = bit_depths[0]; |
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for (j = 1; j < histogram_size; ++j) { |
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if (max_depth < bit_depths[j]) { |
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max_depth = bit_depths[j]; |
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} |
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} |
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if (max_depth <= tree_depth_limit) { |
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break; |
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} |
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} |
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} |
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} |
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// ----------------------------------------------------------------------------- |
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// Coding of the Huffman tree values |
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static HuffmanTreeToken* CodeRepeatedValues(int repetitions, |
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HuffmanTreeToken* tokens, |
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int value, int prev_value) { |
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assert(value <= MAX_ALLOWED_CODE_LENGTH); |
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if (value != prev_value) { |
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tokens->code = value; |
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tokens->extra_bits = 0; |
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++tokens; |
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--repetitions; |
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} |
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while (repetitions >= 1) { |
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if (repetitions < 3) { |
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int i; |
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for (i = 0; i < repetitions; ++i) { |
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tokens->code = value; |
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tokens->extra_bits = 0; |
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++tokens; |
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} |
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break; |
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} else if (repetitions < 7) { |
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tokens->code = 16; |
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tokens->extra_bits = repetitions - 3; |
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++tokens; |
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break; |
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} else { |
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tokens->code = 16; |
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tokens->extra_bits = 3; |
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++tokens; |
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repetitions -= 6; |
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} |
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} |
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return tokens; |
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} |
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static HuffmanTreeToken* CodeRepeatedZeros(int repetitions, |
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HuffmanTreeToken* tokens) { |
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while (repetitions >= 1) { |
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if (repetitions < 3) { |
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int i; |
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for (i = 0; i < repetitions; ++i) { |
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tokens->code = 0; // 0-value |
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tokens->extra_bits = 0; |
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++tokens; |
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} |
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break; |
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} else if (repetitions < 11) { |
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tokens->code = 17; |
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tokens->extra_bits = repetitions - 3; |
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++tokens; |
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break; |
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} else if (repetitions < 139) { |
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tokens->code = 18; |
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tokens->extra_bits = repetitions - 11; |
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++tokens; |
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break; |
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} else { |
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tokens->code = 18; |
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tokens->extra_bits = 0x7f; // 138 repeated 0s |
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++tokens; |
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repetitions -= 138; |
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} |
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} |
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return tokens; |
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} |
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int VP8LCreateCompressedHuffmanTree(const HuffmanTreeCode* const tree, |
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HuffmanTreeToken* tokens, int max_tokens) { |
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HuffmanTreeToken* const starting_token = tokens; |
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HuffmanTreeToken* const ending_token = tokens + max_tokens; |
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const int depth_size = tree->num_symbols; |
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int prev_value = 8; // 8 is the initial value for rle. |
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int i = 0; |
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assert(tokens != NULL); |
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while (i < depth_size) { |
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const int value = tree->code_lengths[i]; |
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int k = i + 1; |
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int runs; |
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while (k < depth_size && tree->code_lengths[k] == value) ++k; |
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runs = k - i; |
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if (value == 0) { |
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tokens = CodeRepeatedZeros(runs, tokens); |
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} else { |
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tokens = CodeRepeatedValues(runs, tokens, value, prev_value); |
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prev_value = value; |
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} |
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i += runs; |
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assert(tokens <= ending_token); |
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} |
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(void)ending_token; // suppress 'unused variable' warning |
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return (int)(tokens - starting_token); |
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} |
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// ----------------------------------------------------------------------------- |
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// Pre-reversed 4-bit values. |
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static const uint8_t kReversedBits[16] = { |
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0x0, 0x8, 0x4, 0xc, 0x2, 0xa, 0x6, 0xe, |
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0x1, 0x9, 0x5, 0xd, 0x3, 0xb, 0x7, 0xf |
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}; |
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static uint32_t ReverseBits(int num_bits, uint32_t bits) { |
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uint32_t retval = 0; |
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int i = 0; |
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while (i < num_bits) { |
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i += 4; |
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retval |= kReversedBits[bits & 0xf] << (MAX_ALLOWED_CODE_LENGTH + 1 - i); |
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bits >>= 4; |
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} |
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retval >>= (MAX_ALLOWED_CODE_LENGTH + 1 - num_bits); |
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return retval; |
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} |
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// Get the actual bit values for a tree of bit depths. |
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static void ConvertBitDepthsToSymbols(HuffmanTreeCode* const tree) { |
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// 0 bit-depth means that the symbol does not exist. |
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int i; |
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int len; |
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uint32_t next_code[MAX_ALLOWED_CODE_LENGTH + 1]; |
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int depth_count[MAX_ALLOWED_CODE_LENGTH + 1] = { 0 }; |
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assert(tree != NULL); |
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len = tree->num_symbols; |
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for (i = 0; i < len; ++i) { |
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const int code_length = tree->code_lengths[i]; |
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assert(code_length <= MAX_ALLOWED_CODE_LENGTH); |
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++depth_count[code_length]; |
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} |
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depth_count[0] = 0; // ignore unused symbol |
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next_code[0] = 0; |
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{ |
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uint32_t code = 0; |
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for (i = 1; i <= MAX_ALLOWED_CODE_LENGTH; ++i) { |
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code = (code + depth_count[i - 1]) << 1; |
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next_code[i] = code; |
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} |
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} |
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for (i = 0; i < len; ++i) { |
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const int code_length = tree->code_lengths[i]; |
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tree->codes[i] = ReverseBits(code_length, next_code[code_length]++); |
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} |
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} |
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// ----------------------------------------------------------------------------- |
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// Main entry point |
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void VP8LCreateHuffmanTree(uint32_t* const histogram, int tree_depth_limit, |
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uint8_t* const buf_rle, |
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HuffmanTree* const huff_tree, |
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HuffmanTreeCode* const huff_code) { |
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const int num_symbols = huff_code->num_symbols; |
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memset(buf_rle, 0, num_symbols * sizeof(*buf_rle)); |
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OptimizeHuffmanForRle(num_symbols, buf_rle, histogram); |
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GenerateOptimalTree(histogram, num_symbols, huff_tree, tree_depth_limit, |
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huff_code->code_lengths); |
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// Create the actual bit codes for the bit lengths. |
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ConvertBitDepthsToSymbols(huff_code); |
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}
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