@ -35,14 +35,24 @@ three machines are the same. Simple so far.
Let's next look at the most common cross-compilation setup. Let's
suppose you are on a 64 bit OSX machine and you are cross compiling a
binary that will run on a 32 bit ARM Linux board. In this case your
*build machine* is 64 bit OSX and both your *host* and *target
machines* are 32 bit ARM Linux. This should be quite understandable as
well.
It gets a bit trickier when we think about how the cross compiler was
generated. It was built and it runs on a specific platform but the
output it generates is for a different platform. In this case *build*
and *host machines* are the same, but *target machine* is different.
*build machine* is 64 bit OSX, your *host machine* is 32 bit ARM Linux
and your *target machine* is irrelevant (but defaults to the same value
as the *host machine* ). This should be quite understandable as well.
The usual mistake in this case is to call the OSX system the *host* and
the ARM Linux board the *target* . That's because these were their actual
names when the cross-compiler itself was compiled! Let's assume the
cross-compiler was created on OSX too. When that happened the *build*
and *host machines* were the same OSX and different from the ARM Linux
*target machine*.
In a nutshell, the typical mistake assumes that the terms *build* ,
*host* and *target* refer to some fixed positions whereas they're
actually relative to where the current compiler is running. Think of
*host* as a *child* of the current compiler and *target* as an optional
*grand-child*. Compilers don't change their terminology when they're
creating another compiler, that would at the very least make their user
interface much more complex.
The most complicated case is when you cross-compile a cross
compiler. As an example you can, on a Linux machine, generate a cross
@ -56,8 +66,8 @@ Wikipedia or the net in general. It is very common for them to get
build, host and target mixed up, even in consecutive sentences, which
can leave you puzzled until you figure it out.
A lot of confusion stems from the fact that when you cross-compile
something, the 3 systems (*build*, *host* , and *target* ) used when
Again note that when you cross-compile something,
the 3 systems (*build*, *host* , and *target* ) used when
building the cross compiler don't align with the ones used when
building something with that newly-built cross compiler. To take our
Canadian Cross scenario from above (for full generality), since its
@ -67,8 +77,8 @@ Linux, the *host machine* of anything we build with it is *MIPS
Linux*. Only the *target machine* of whatever we build with it can be
freely chosen by us, say if we want to build another cross compiler
that runs on MIPS Linux and targets Aarch64 iOS. As this example
hopefully makes clear to you, the platforms are shifted over to the
left by one position.
hopefully makes clear to you, the machine names are relative and
shifted over to the left by one position.
If you did not understand all of the details, don't worry. For most
people it takes a while to wrap their head around these