mparser: Don't create an exception to pass to mlog.warning

Just call `mlog.code_line` directly, since the exception is never raised.
pull/11179/head
Dylan Baker 2 years ago committed by Eli Schwartz
parent 7460ab20cd
commit 8f9c6c10c4
  1. 7
      mesonbuild/mparser.py

@ -193,11 +193,10 @@ class Lexer:
elif tid in {'string', 'fstring'}:
# Handle here and not on the regexp to give a better error message.
if match_text.find("\n") != -1:
msg = ParseException("Newline character in a string detected, use ''' (three single quotes) "
msg = ("Newline character in a string detected, use ''' (three single quotes) "
"for multiline strings instead.\n"
"This will become a hard error in a future Meson release.",
self.getline(line_start), lineno, col)
mlog.warning(msg, location=BaseNode(lineno, col, filename))
"This will become a hard error in a future Meson release.")
mlog.warning(mlog.code_line(msg, self.getline(line_start), col), location=BaseNode(lineno, col, filename))
value = match_text[2 if tid == 'fstring' else 1:-1]
try:
value = ESCAPE_SEQUENCE_SINGLE_RE.sub(decode_match, value)

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