allow fortran submodule to have same name as module

pull/5039/head
Michael Hirsch, Ph.D 6 years ago
parent 40b5abd668
commit 2a830743cc
  1. 69
      mesonbuild/backend/ninjabackend.py

@ -1824,6 +1824,7 @@ rule FORTRAN_DEP_HACK%s
modre = re.compile(r"\s*\bmodule\b\s+(\w+)\s*$", re.IGNORECASE)
submodre = re.compile(r"\s*\bsubmodule\b\s+\((\w+:?\w+)\)\s+(\w+)\s*$", re.IGNORECASE)
module_files = {}
submodule_files = {}
for s in target.get_sources():
# FIXME, does not work for Fortran sources generated by
# custom_target() and generator() as those are run after
@ -1847,15 +1848,16 @@ rule FORTRAN_DEP_HACK%s
else:
submodmatch = submodre.match(line)
if submodmatch is not None:
submodname = submodmatch.group(2).lower()
if submodname in module_files:
# '_' is arbitrarily used to distinguish submod from mod.
submodname = '_' + submodmatch.group(2).lower()
if submodname in submodule_files:
raise InvalidArguments(
'Namespace collision: submodule %s defined in '
'two files %s and %s.' %
(submodname, module_files[submodname], s))
module_files[submodname] = s
(submodname, submodule_files[submodname], s))
submodule_files[submodname] = s
self.fortran_deps[target.get_basename()] = module_files
self.fortran_deps[target.get_basename()] = {**module_files, **submodule_files}
def get_fortran_deps(self, compiler: FortranCompiler, src: str, target) -> List[str]:
"""
@ -1865,6 +1867,63 @@ rule FORTRAN_DEP_HACK%s
dirname = Path(self.get_target_private_dir(target))
tdeps = self.fortran_deps[target.get_basename()]
srcdir = Path(self.source_dir)
<<<<<<< HEAD
=======
with src.open(encoding='ascii', errors='ignore') as f:
for line in f:
usematch = usere.match(line)
if usematch is not None:
usename = usematch.group(1).lower()
if usename == 'intrinsic': # this keeps the regex simpler
continue
if usename not in tdeps:
# The module is not provided by any source file. This
# is due to:
# a) missing file/typo/etc
# b) using a module provided by the compiler, such as
# OpenMP
# There's no easy way to tell which is which (that I
# know of) so just ignore this and go on. Ideally we
# would print a warning message to the user but this is
# a common occurrence, which would lead to lots of
# distracting noise.
continue
srcfile = srcdir / tdeps[usename].fname
if not srcfile.is_file():
if srcfile.name != src.name: # generated source file
pass
else: # subproject
continue
elif srcfile.samefile(src): # self-reference
continue
mod_name = compiler.module_name_to_filename(usename)
mod_files.append(str(dirname / mod_name))
else:
submodmatch = submodre.match(line)
if submodmatch is not None:
parents = submodmatch.group(1).lower().split(':')
assert len(parents) in (1, 2), (
'submodule ancestry must be specified as'
' ancestor:parent but Meson found {}'.parents)
if len(parents) == 2:
parents[1] = '_' + parents[1]
for parent in parents:
if parent not in tdeps:
raise MesonException("submodule {} relies on parent module {} that was not found.".format(submodmatch.group(2).lower(), parent))
submodsrcfile = srcdir / tdeps[parent].fname
if not submodsrcfile.is_file():
if submodsrcfile.name != src.name: # generated source file
pass
else: # subproject
continue
elif submodsrcfile.samefile(src): # self-reference
continue
mod_name = compiler.module_name_to_filename(parent)
mod_files.append(str(dirname / mod_name))
>>>>>>> allow fortran submodule to have same name as module
mod_files = _scan_fortran_file_deps(src, srcdir, dirname, tdeps, compiler)
return mod_files

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