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/*
--------------------------------------------------------------------
By Bob Jenkins, September 1996. recycle.c
You may use this code in any way you wish, and it is free. No warranty.
This manages memory for commonly-allocated structures.
It allocates RESTART to REMAX items at a time.
Timings have shown that, if malloc is used for every new structure,
malloc will consume about 90% of the time in a program. This
module cuts down the number of mallocs by an order of magnitude.
This also decreases memory fragmentation, and freeing structures
only requires freeing the root.
--------------------------------------------------------------------
*/
#ifndef STANDARD
# include "standard.h"
#endif
#ifndef RECYCLE
# include "recycle.h"
#endif
reroot *remkroot(size)
size_t size;
{
reroot *r = (reroot *)remalloc(sizeof(reroot), "recycle.c, root");
r->list = (recycle *)0;
r->trash = (recycle *)0;
r->size = align(size);
r->logsize = RESTART;
r->numleft = 0;
return r;
}
void refree(r)
struct reroot *r;
{
recycle *temp;
if (temp = r->list) while (r->list)
{
temp = r->list->next;
free((char *)r->list);
r->list = temp;
}
free((char *)r);
return;
}
/* to be called from the macro renew only */
char *renewx(r)
struct reroot *r;
{
recycle *temp;
if (r->trash)
{ /* pull a node off the trash heap */
temp = r->trash;
r->trash = temp->next;
(void)memset((void *)temp, 0, r->size);
}
else
{ /* allocate a new block of nodes */
r->numleft = r->size*((ub4)1<<r->logsize);
if (r->numleft < REMAX) ++r->logsize;
temp = (recycle *)remalloc(sizeof(recycle) + r->numleft,
"recycle.c, data");
temp->next = r->list;
r->list = temp;
r->numleft-=r->size;
temp = (recycle *)((char *)(r->list+1)+r->numleft);
}
return (char *)temp;
}
char *remalloc(len, purpose)
size_t len;
char *purpose;
{
char *x = (char *)malloc(len);
if (!x)
{
fprintf(stderr, "malloc of %d failed for %s\n",
len, purpose);
exit(SUCCESS);
}
return x;
}