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The C based gRPC (C++, Python, Ruby, Objective-C, PHP, C#)
https://grpc.io/
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50 lines
1.5 KiB
50 lines
1.5 KiB
# Copyright 2020 The gRPC Authors |
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# |
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# Licensed under the Apache License, Version 2.0 (the "License"); |
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# you may not use this file except in compliance with the License. |
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# You may obtain a copy of the License at |
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# |
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# http://www.apache.org/licenses/LICENSE-2.0 |
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# |
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# Unless required by applicable law or agreed to in writing, software |
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# distributed under the License is distributed on an "AS IS" BASIS, |
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# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. |
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# See the License for the specific language governing permissions and |
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# limitations under the License. |
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"""Download and unzip the target file to the destination.""" |
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from __future__ import print_function |
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import os |
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import sys |
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import tempfile |
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import zipfile |
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import requests |
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def main(): |
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if len(sys.argv) != 3: |
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print("Usage: python download_and_unzip.py [zipfile-url] [destination]") |
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sys.exit(1) |
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download_url = sys.argv[1] |
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destination = sys.argv[2] |
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with tempfile.TemporaryFile() as tmp_file: |
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r = requests.get(download_url) |
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if r.status_code != requests.codes.ok: |
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print( |
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'Download %s failed with [%d] "%s"' |
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% (download_url, r.status_code, r.text()) |
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) |
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sys.exit(1) |
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else: |
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tmp_file.write(r.content) |
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print("Successfully downloaded from %s", download_url) |
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with zipfile.ZipFile(tmp_file, "r") as target_zip_file: |
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target_zip_file.extractall(destination) |
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print("Successfully unzip to %s" % destination) |
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if __name__ == "__main__": |
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main()
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