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The C based gRPC (C++, Python, Ruby, Objective-C, PHP, C#)
https://grpc.io/
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57 lines
1.9 KiB
57 lines
1.9 KiB
6 years ago
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# Copyright 2019 The gRPC Authors
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#
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# Licensed under the Apache License, Version 2.0 (the "License");
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# you may not use this file except in compliance with the License.
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# You may obtain a copy of the License at
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#
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# http://www.apache.org/licenses/LICENSE-2.0
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#
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# Unless required by applicable law or agreed to in writing, software
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# distributed under the License is distributed on an "AS IS" BASIS,
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# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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# See the License for the specific language governing permissions and
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# limitations under the License.
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"""This example handles rich error status in client-side."""
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from __future__ import print_function
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import logging
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import grpc
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from grpc_status import rpc_status
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from google.rpc import error_details_pb2
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from examples.protos import helloworld_pb2
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from examples.protos import helloworld_pb2_grpc
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_LOGGER = logging.getLogger(__name__)
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def process(stub):
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try:
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response = stub.SayHello(helloworld_pb2.HelloRequest(name='Alice'))
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_LOGGER.info('Call success: %s', response.message)
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except grpc.RpcError as rpc_error:
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_LOGGER.error('Call failure: %s', rpc_error)
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status = rpc_status.from_call(rpc_error)
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for detail in status.details:
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if detail.Is(error_details_pb2.QuotaFailure.DESCRIPTOR):
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info = error_details_pb2.QuotaFailure()
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detail.Unpack(info)
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_LOGGER.error('Quota failure: %s', info)
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else:
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raise RuntimeError('Unexpected failure: %s' % detail)
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def main():
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# NOTE(gRPC Python Team): .close() is possible on a channel and should be
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# used in circumstances in which the with statement does not fit the needs
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# of the code.
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with grpc.insecure_channel('localhost:50051') as channel:
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stub = helloworld_pb2_grpc.GreeterStub(channel)
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process(stub)
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if __name__ == '__main__':
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logging.basicConfig()
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main()
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