The C based gRPC (C++, Python, Ruby, Objective-C, PHP, C#) https://grpc.io/
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# Copyright 2019 The gRPC Authors
#
# Licensed under the Apache License, Version 2.0 (the "License");
# you may not use this file except in compliance with the License.
# You may obtain a copy of the License at
#
# http://www.apache.org/licenses/LICENSE-2.0
#
# Unless required by applicable law or agreed to in writing, software
# distributed under the License is distributed on an "AS IS" BASIS,
# WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
# See the License for the specific language governing permissions and
# limitations under the License.
"""This example handles rich error status in client-side."""
from __future__ import print_function
import logging
import grpc
from grpc_status import rpc_status
from google.rpc import error_details_pb2
from examples.protos import helloworld_pb2
from examples.protos import helloworld_pb2_grpc
_LOGGER = logging.getLogger(__name__)
def process(stub):
try:
response = stub.SayHello(helloworld_pb2.HelloRequest(name='Alice'))
_LOGGER.info('Call success: %s', response.message)
except grpc.RpcError as rpc_error:
_LOGGER.error('Call failure: %s', rpc_error)
status = rpc_status.from_call(rpc_error)
for detail in status.details:
if detail.Is(error_details_pb2.QuotaFailure.DESCRIPTOR):
info = error_details_pb2.QuotaFailure()
detail.Unpack(info)
_LOGGER.error('Quota failure: %s', info)
else:
raise RuntimeError('Unexpected failure: %s' % detail)
def main():
# NOTE(gRPC Python Team): .close() is possible on a channel and should be
# used in circumstances in which the with statement does not fit the needs
# of the code.
with grpc.insecure_channel('localhost:50051') as channel:
stub = helloworld_pb2_grpc.GreeterStub(channel)
process(stub)
if __name__ == '__main__':
logging.basicConfig()
main()