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262 lines
6.5 KiB
262 lines
6.5 KiB
/* |
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* FFT/IFFT transforms |
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* Copyright (c) 2002 Fabrice Bellard. |
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* |
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* This file is part of FFmpeg. |
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* |
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* FFmpeg is free software; you can redistribute it and/or |
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* modify it under the terms of the GNU Lesser General Public |
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* License as published by the Free Software Foundation; either |
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* version 2.1 of the License, or (at your option) any later version. |
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* |
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* FFmpeg is distributed in the hope that it will be useful, |
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* but WITHOUT ANY WARRANTY; without even the implied warranty of |
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* MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU |
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* Lesser General Public License for more details. |
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* |
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* You should have received a copy of the GNU Lesser General Public |
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* License along with FFmpeg; if not, write to the Free Software |
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* Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA 02110-1301 USA |
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*/ |
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/** |
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* @file fft.c |
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* FFT/IFFT transforms. |
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*/ |
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#include "dsputil.h" |
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/** |
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* The size of the FFT is 2^nbits. If inverse is TRUE, inverse FFT is |
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* done |
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*/ |
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int ff_fft_init(FFTContext *s, int nbits, int inverse) |
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{ |
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int i, j, m, n; |
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float alpha, c1, s1, s2; |
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s->nbits = nbits; |
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n = 1 << nbits; |
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s->exptab = av_malloc((n / 2) * sizeof(FFTComplex)); |
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if (!s->exptab) |
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goto fail; |
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s->revtab = av_malloc(n * sizeof(uint16_t)); |
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if (!s->revtab) |
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goto fail; |
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s->inverse = inverse; |
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s2 = inverse ? 1.0 : -1.0; |
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for(i=0;i<(n/2);i++) { |
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alpha = 2 * M_PI * (float)i / (float)n; |
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c1 = cos(alpha); |
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s1 = sin(alpha) * s2; |
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s->exptab[i].re = c1; |
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s->exptab[i].im = s1; |
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} |
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s->fft_calc = ff_fft_calc_c; |
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s->imdct_calc = ff_imdct_calc; |
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s->exptab1 = NULL; |
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/* compute constant table for HAVE_SSE version */ |
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#if defined(HAVE_MMX) \ |
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|| (defined(HAVE_ALTIVEC) && !defined(ALTIVEC_USE_REFERENCE_C_CODE)) |
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{ |
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int has_vectors = mm_support(); |
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if (has_vectors) { |
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#if defined(HAVE_MMX) |
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if (has_vectors & MM_3DNOWEXT) { |
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/* 3DNowEx for K7/K8 */ |
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s->imdct_calc = ff_imdct_calc_3dn2; |
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s->fft_calc = ff_fft_calc_3dn2; |
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} else if (has_vectors & MM_3DNOW) { |
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/* 3DNow! for K6-2/3 */ |
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s->fft_calc = ff_fft_calc_3dn; |
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} else if (has_vectors & MM_SSE) { |
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/* SSE for P3/P4 */ |
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s->imdct_calc = ff_imdct_calc_sse; |
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s->fft_calc = ff_fft_calc_sse; |
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} |
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#else /* HAVE_MMX */ |
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if (has_vectors & MM_ALTIVEC) |
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s->fft_calc = ff_fft_calc_altivec; |
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#endif |
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} |
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if (s->fft_calc != ff_fft_calc_c) { |
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int np, nblocks, np2, l; |
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FFTComplex *q; |
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np = 1 << nbits; |
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nblocks = np >> 3; |
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np2 = np >> 1; |
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s->exptab1 = av_malloc(np * 2 * sizeof(FFTComplex)); |
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if (!s->exptab1) |
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goto fail; |
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q = s->exptab1; |
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do { |
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for(l = 0; l < np2; l += 2 * nblocks) { |
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*q++ = s->exptab[l]; |
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*q++ = s->exptab[l + nblocks]; |
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q->re = -s->exptab[l].im; |
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q->im = s->exptab[l].re; |
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q++; |
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q->re = -s->exptab[l + nblocks].im; |
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q->im = s->exptab[l + nblocks].re; |
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q++; |
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} |
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nblocks = nblocks >> 1; |
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} while (nblocks != 0); |
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av_freep(&s->exptab); |
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} |
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} |
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#endif |
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/* compute bit reverse table */ |
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for(i=0;i<n;i++) { |
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m=0; |
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for(j=0;j<nbits;j++) { |
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m |= ((i >> j) & 1) << (nbits-j-1); |
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} |
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s->revtab[i]=m; |
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} |
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return 0; |
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fail: |
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av_freep(&s->revtab); |
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av_freep(&s->exptab); |
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av_freep(&s->exptab1); |
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return -1; |
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} |
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/* butter fly op */ |
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#define BF(pre, pim, qre, qim, pre1, pim1, qre1, qim1) \ |
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{\ |
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FFTSample ax, ay, bx, by;\ |
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bx=pre1;\ |
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by=pim1;\ |
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ax=qre1;\ |
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ay=qim1;\ |
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pre = (bx + ax);\ |
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pim = (by + ay);\ |
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qre = (bx - ax);\ |
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qim = (by - ay);\ |
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} |
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#define MUL16(a,b) ((a) * (b)) |
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#define CMUL(pre, pim, are, aim, bre, bim) \ |
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{\ |
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pre = (MUL16(are, bre) - MUL16(aim, bim));\ |
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pim = (MUL16(are, bim) + MUL16(bre, aim));\ |
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} |
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/** |
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* Do a complex FFT with the parameters defined in ff_fft_init(). The |
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* input data must be permuted before with s->revtab table. No |
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* 1.0/sqrt(n) normalization is done. |
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*/ |
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void ff_fft_calc_c(FFTContext *s, FFTComplex *z) |
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{ |
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int ln = s->nbits; |
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int j, np, np2; |
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int nblocks, nloops; |
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register FFTComplex *p, *q; |
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FFTComplex *exptab = s->exptab; |
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int l; |
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FFTSample tmp_re, tmp_im; |
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np = 1 << ln; |
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/* pass 0 */ |
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p=&z[0]; |
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j=(np >> 1); |
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do { |
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BF(p[0].re, p[0].im, p[1].re, p[1].im, |
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p[0].re, p[0].im, p[1].re, p[1].im); |
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p+=2; |
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} while (--j != 0); |
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/* pass 1 */ |
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p=&z[0]; |
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j=np >> 2; |
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if (s->inverse) { |
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do { |
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BF(p[0].re, p[0].im, p[2].re, p[2].im, |
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p[0].re, p[0].im, p[2].re, p[2].im); |
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BF(p[1].re, p[1].im, p[3].re, p[3].im, |
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p[1].re, p[1].im, -p[3].im, p[3].re); |
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p+=4; |
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} while (--j != 0); |
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} else { |
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do { |
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BF(p[0].re, p[0].im, p[2].re, p[2].im, |
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p[0].re, p[0].im, p[2].re, p[2].im); |
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BF(p[1].re, p[1].im, p[3].re, p[3].im, |
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p[1].re, p[1].im, p[3].im, -p[3].re); |
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p+=4; |
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} while (--j != 0); |
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} |
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/* pass 2 .. ln-1 */ |
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nblocks = np >> 3; |
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nloops = 1 << 2; |
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np2 = np >> 1; |
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do { |
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p = z; |
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q = z + nloops; |
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for (j = 0; j < nblocks; ++j) { |
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BF(p->re, p->im, q->re, q->im, |
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p->re, p->im, q->re, q->im); |
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p++; |
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q++; |
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for(l = nblocks; l < np2; l += nblocks) { |
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CMUL(tmp_re, tmp_im, exptab[l].re, exptab[l].im, q->re, q->im); |
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BF(p->re, p->im, q->re, q->im, |
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p->re, p->im, tmp_re, tmp_im); |
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p++; |
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q++; |
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} |
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p += nloops; |
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q += nloops; |
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} |
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nblocks = nblocks >> 1; |
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nloops = nloops << 1; |
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} while (nblocks != 0); |
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} |
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/** |
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* Do the permutation needed BEFORE calling ff_fft_calc() |
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*/ |
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void ff_fft_permute(FFTContext *s, FFTComplex *z) |
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{ |
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int j, k, np; |
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FFTComplex tmp; |
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const uint16_t *revtab = s->revtab; |
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/* reverse */ |
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np = 1 << s->nbits; |
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for(j=0;j<np;j++) { |
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k = revtab[j]; |
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if (k < j) { |
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tmp = z[k]; |
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z[k] = z[j]; |
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z[j] = tmp; |
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} |
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} |
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} |
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void ff_fft_end(FFTContext *s) |
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{ |
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av_freep(&s->revtab); |
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av_freep(&s->exptab); |
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av_freep(&s->exptab1); |
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} |
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