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@ -28,7 +28,7 @@ |
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* The size of the FFT is 2^nbits. If inverse is TRUE, inverse FFT is |
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* done
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*/ |
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int fft_init(FFTContext *s, int nbits, int inverse) |
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int ff_fft_init(FFTContext *s, int nbits, int inverse) |
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{ |
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int i, j, m, n; |
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float alpha, c1, s1, s2; |
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@ -53,7 +53,7 @@ int fft_init(FFTContext *s, int nbits, int inverse) |
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s->exptab[i].re = c1; |
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s->exptab[i].im = s1; |
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} |
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s->fft_calc = fft_calc_c; |
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s->fft_calc = ff_fft_calc_c; |
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s->exptab1 = NULL; |
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/* compute constant table for HAVE_SSE version */ |
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@ -94,9 +94,9 @@ int fft_init(FFTContext *s, int nbits, int inverse) |
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} while (nblocks != 0); |
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av_freep(&s->exptab); |
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#if defined(HAVE_MMX) |
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s->fft_calc = fft_calc_sse; |
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s->fft_calc = ff_fft_calc_sse; |
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#else |
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s->fft_calc = fft_calc_altivec; |
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s->fft_calc = ff_fft_calc_altivec; |
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#endif |
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} |
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} |
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@ -142,11 +142,11 @@ int fft_init(FFTContext *s, int nbits, int inverse) |
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} |
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/**
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* Do a complex FFT with the parameters defined in fft_init(). The |
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* Do a complex FFT with the parameters defined in ff_fft_init(). The |
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* input data must be permuted before with s->revtab table. No |
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* 1.0/sqrt(n) normalization is done.
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*/ |
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void fft_calc_c(FFTContext *s, FFTComplex *z) |
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void ff_fft_calc_c(FFTContext *s, FFTComplex *z) |
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{ |
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int ln = s->nbits; |
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int j, np, np2; |
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@ -221,9 +221,9 @@ void fft_calc_c(FFTContext *s, FFTComplex *z) |
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} |
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/**
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* Do the permutation needed BEFORE calling fft_calc() |
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* Do the permutation needed BEFORE calling ff_fft_calc() |
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*/ |
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void fft_permute(FFTContext *s, FFTComplex *z) |
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void ff_fft_permute(FFTContext *s, FFTComplex *z) |
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{ |
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int j, k, np; |
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FFTComplex tmp; |
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@ -241,7 +241,7 @@ void fft_permute(FFTContext *s, FFTComplex *z) |
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} |
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} |
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void fft_end(FFTContext *s) |
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void ff_fft_end(FFTContext *s) |
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{ |
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av_freep(&s->revtab); |
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av_freep(&s->exptab); |
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